2x+2y^2+20x+12y+50=0

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Solution for 2x+2y^2+20x+12y+50=0 equation:


Simplifying
2x + 2y2 + 20x + 12y + 50 = 0

Reorder the terms:
50 + 2x + 20x + 12y + 2y2 = 0

Combine like terms: 2x + 20x = 22x
50 + 22x + 12y + 2y2 = 0

Solving
50 + 22x + 12y + 2y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-50' to each side of the equation.
50 + 22x + 12y + -50 + 2y2 = 0 + -50

Reorder the terms:
50 + -50 + 22x + 12y + 2y2 = 0 + -50

Combine like terms: 50 + -50 = 0
0 + 22x + 12y + 2y2 = 0 + -50
22x + 12y + 2y2 = 0 + -50

Combine like terms: 0 + -50 = -50
22x + 12y + 2y2 = -50

Add '-12y' to each side of the equation.
22x + 12y + -12y + 2y2 = -50 + -12y

Combine like terms: 12y + -12y = 0
22x + 0 + 2y2 = -50 + -12y
22x + 2y2 = -50 + -12y

Add '-2y2' to each side of the equation.
22x + 2y2 + -2y2 = -50 + -12y + -2y2

Combine like terms: 2y2 + -2y2 = 0
22x + 0 = -50 + -12y + -2y2
22x = -50 + -12y + -2y2

Divide each side by '22'.
x = -2.272727273 + -0.5454545455y + -0.09090909091y2

Simplifying
x = -2.272727273 + -0.5454545455y + -0.09090909091y2

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